What is implicit derivative of θ(x),tan(θ(x))= x/(35) ?

The answer to implicit derivative of θ(x),tan(θ(x))= x/(35) is derivative of θ= 1/(35sec^2(θ))

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implicit derivative of θ(x),tan(θ(x))= x/(35)

implicit derivative

\frac{d}{d x} (θ (x)), tan (θ (x)) = \frac{x}{35}

\frac{d}{d x} (θ) = \frac{1}{35 sec ^{2} ( θ )}

Solution steps

tan (θ) = \frac{x}{35}

Treat

θ

θ (x)

Differentiate both sides:

sec^{2} (θ) \frac{d}{d x} (θ) = \frac{1}{35}

Isolate

\frac{d}{d x} (θ) : \frac{d}{d x} (θ) = \frac{1}{35 sec ^{2} ( θ )}

\frac{d}{d x} (θ) = \frac{1}{35 sec ^{2} ( θ )}

(x) \frac{d y}{d x} + y = \frac{1}{y ^{2}}

\frac{x ^{2} - 9 x + 20}{( x + 2 ) ( x - 2 )}

\int 20 x^{\frac{3}{2}} d x

\frac{2}{2 s - 1}

\frac{d}{d x} (5^{- \frac{x}{2}})

What is implicit derivative of θ(x),tan(θ(x))= x/(35) ?
The answer to implicit derivative of θ(x),tan(θ(x))= x/(35) is derivative of θ= 1/(35sec^2(θ))