What is the limit as x approaches 0+of (-4x^2-6x)/x ?

The limit as x approaches 0+of (-4x^2-6x)/x is -6

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limit as x approaches 0+of (-4x^2-6x)/x

x \to 0 + lim (\frac{- 4 x ^{2} - 6 x}{x})

- 6

Solution steps

x \to 0 + lim (\frac{- 4 x ^{2} - 6 x}{x})

Simplify

\frac{- 4 x ^{2} - 6 x}{x} : - 2 (2 x + 3)

= x \to 0 + lim (- 2 (2 x + 3))

Plug in the value

x = 0

= - 2 (2 \cdot 0 + 3)

Simplify

= - 6

f (x) = \frac{3}{4} x^{8}

\frac{d}{d y} (3 x (5 + y)^{- 1})

y = 2 x, y = x^{2} - 3

\int \frac{1}{4 x ^{2} - 16 x + 52} d x

\frac{\partial ^{2}}{\partial y ^{2}} (y^{4} cos (2 x))

What is the limit as x approaches 0+of (-4x^2-6x)/x ?
The limit as x approaches 0+of (-4x^2-6x)/x is -6