What is the tangent of f(x)=2x^2-9x+10,\at x=3 ?

The tangent of f(x)=2x^2-9x+10,\at x=3 is y=3x-8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=2x^2-9x+10,\at x=3

tangent of

f (x) = 2 x^{2} - 9 x + 10, at x = 3

y = 3 x - 8

Solution steps

Find the tangent point:

(3, 1)

Find the slope of

f (x) = 2 x^{2} - 9 x + 10 : \frac{df ( x )}{d x} = 4 x - 9

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 3

Find the line with slope m=

3

and passing through

(3, 1) : y = 3 x - 8

y = 3 x - 8

\frac{d}{d x} (x^{4} + x^{2})

\frac{d}{d x} (e^{(6 x - 7 x^{2})})

\int_{- 2}^{2} e^{- x^{2}} d x

y = 2 x - 2 x^{2}

x \to 2 lim (\frac{1}{2} x^{2} - 4 x)

What is the tangent of f(x)=2x^2-9x+10,\at x=3 ?
The tangent of f(x)=2x^2-9x+10,\at x=3 is y=3x-8