What is the derivative of x^4+x^2 ?

The derivative of x^4+x^2 is 4x^3+2x

What is the first derivative of x^4+x^2 ?

The first derivative of x^4+x^2 is 4x^3+2x

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\frac{d}{d x} (x^{4} + x^{2})

4 x^{3} + 2 x

Solution steps

\frac{d}{d x} (x^{4} + x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{4}) + \frac{d}{d x} (x^{2})

\frac{d}{d x} (x^{4}) = 4 x^{3}

\frac{d}{d x} (x^{2}) = 2 x

= 4 x^{3} + 2 x

\frac{d}{d x} (e^{(6 x - 7 x^{2})})

\int_{- 2}^{2} e^{- x^{2}} d x

y = 2 x - 2 x^{2}

x \to 2 lim (\frac{1}{2} x^{2} - 4 x)

2 e^{2 t}

What is the derivative of x^4+x^2 ?
The derivative of x^4+x^2 is 4x^3+2x
What is the first derivative of x^4+x^2 ?
The first derivative of x^4+x^2 is 4x^3+2x