What is the derivative of 2e^{2t} ?

The derivative of 2e^{2t} is 4e^{2t}

What is the first derivative of 2e^{2t} ?

The first derivative of 2e^{2t} is 4e^{2t}

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derivative of

2 e^{2 t}

4 e^{2 t}

Solution steps

\frac{d}{d t} (2 e^{2 t})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d t} (e^{2 t})

Apply the chain rule:

e^{2 t} \frac{d}{d t} (2 t)

= e^{2 t} \frac{d}{d t} (2 t)

\frac{d}{d t} (2 t) = 2

= 2 e^{2 t} \cdot 2

Simplify

= 4 e^{2 t}

x = - 2, x = 3, y = 2 x^{2} + 2, y = 0

2 x^{2} + x - 1, at x = - 1

\int cot^{5} (x) sin^{4} (x) d x

\frac{d y}{d x}, cos (x + y) = sin (x) sin (y)

\frac{d}{d x} (e^{2} x)

What is the derivative of 2e^{2t} ?
The derivative of 2e^{2t} is 4e^{2t}
What is the first derivative of 2e^{2t} ?
The first derivative of 2e^{2t} is 4e^{2t}