What is the tangent of 1/(2x+2),\at x=5 ?

The tangent of 1/(2x+2),\at x=5 is y=-1/72 x+11/72

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tangent of 1/(2x+2),\at x=5

tangent of

\frac{1}{2 x + 2}, at x = 5

y = - \frac{1}{72} x + \frac{11}{72}

Solution steps

Find the tangent point:

(5, \frac{1}{12})

Find the slope of

y = \frac{1}{2 x + 2} : \frac{d y}{d x} = - \frac{1}{2 ( x + 1 ) ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{1}{72}

Find the line with slope m=

- \frac{1}{72}

and passing through

(5, \frac{1}{12}) : y = - \frac{1}{72} x + \frac{11}{72}

y = - \frac{1}{72} x + \frac{11}{72}

(4 - x^{2}) \frac{d y}{d x} = 2 y

y = (\frac{x + 1}{x - 3})^{2}, (7, 4)

\int 2 cos^{2} (\frac{x}{2}) d x

\int \frac{1}{t ln ( t )} d t

y = 5 e^{x} + x, (0, 5)

What is the tangent of 1/(2x+2),\at x=5 ?
The tangent of 1/(2x+2),\at x=5 is y=-1/72 x+11/72