What is the derivative of (2x^2)/(x^2-1) ?

The derivative of (2x^2)/(x^2-1) is -(4x)/((x^2-1)^2)

What is the first derivative of (2x^2)/(x^2-1) ?

The first derivative of (2x^2)/(x^2-1) is -(4x)/((x^2-1)^2)

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derivative of

\frac{2 x ^{2}}{x ^{2} - 1}

- \frac{4 x}{( x ^{2} - 1 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{2 x ^{2}}{x ^{2} - 1})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (\frac{x ^{2}}{x ^{2} - 1})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= 2 \cdot \frac{\frac{d}{d x} ( x ^{2} ) ( x ^{2} - 1 ) - \frac{d}{d x} ( x ^{2} - 1 ) x ^{2}}{( x ^{2} - 1 ) ^{2}}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (x^{2} - 1) = 2 x

= 2 \cdot \frac{2 x ( x ^{2} - 1 ) - 2 x x ^{2}}{( x ^{2} - 1 ) ^{2}}

Simplify

2 \cdot \frac{2 x ( x ^{2} - 1 ) - 2 x x ^{2}}{( x ^{2} - 1 ) ^{2}} : - \frac{4 x}{( x ^{2} - 1 ) ^{2}}

= - \frac{4 x}{( x ^{2} - 1 ) ^{2}}

\frac{d}{d x} (\frac{e ^{x}}{8 x ^{2}})

\frac{6 x - 1}{2 x + 9}

\int e^{- z^{2}} d z

\int \frac{x}{x ^{2} + 4} d x

x \to 2 lim (- \frac{1}{( x - 2 ) ^{2}})

What is the derivative of (2x^2)/(x^2-1) ?
The derivative of (2x^2)/(x^2-1) is -(4x)/((x^2-1)^2)
What is the first derivative of (2x^2)/(x^2-1) ?
The first derivative of (2x^2)/(x^2-1) is -(4x)/((x^2-1)^2)