What is the derivative of 1+2/x ?

The derivative of 1+2/x is -2/(x^2)

What is the first derivative of 1+2/x ?

The first derivative of 1+2/x is -2/(x^2)

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\frac{d}{d x} (1 + \frac{2}{x})

- \frac{2}{x ^{2}}

Solution steps

\frac{d}{d x} (1 + \frac{2}{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) + \frac{d}{d x} (\frac{2}{x})

\frac{d}{d x} (1) = 0

\frac{d}{d x} (\frac{2}{x}) = - \frac{2}{x ^{2}}

= 0 - \frac{2}{x ^{2}}

Simplify

= - \frac{2}{x ^{2}}

n = 1 \sum \infty 5 (0.8)^{n - 1}

y^{^{''}} + 6 y^{^{'}} = 0

\int_{2}^{\infty} y e^{- 3 y} d y

x \to - 2 - lim (- 2 x + 6)

\int_{0}^{1} \frac{55}{4 y - 1} d y

What is the derivative of 1+2/x ?
The derivative of 1+2/x is -2/(x^2)
What is the first derivative of 1+2/x ?
The first derivative of 1+2/x is -2/(x^2)