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Popular >

f(x)=2xln(x)+x^2-1

Solution

f (x) = 2 x ln (x) + x^{2} - 1

Solution

Domain : x > 0

Range : f (x) \geq 2 W_{0} (\frac{1}{e}) ln (W_{0} (\frac{1}{e})) + W_{0} (\frac{1}{e})^{2} - 1

Intercepts : None

Asymptotes : None

Extreme Points : Minimum (W_{0} (\frac{1}{e}), 2 W_{0} (\frac{1}{e}) ln (W_{0} (\frac{1}{e})) + W_{0} (\frac{1}{e})^{2} - 1)

+1

Interval Notation

Domain : (0, \infty)

Solution steps

Domain of

2 x ln (x) + x^{2} - 1 : x > 0

Range of

2 x ln (x) + x^{2} - 1 : f (x) \geq 2 W_{0} (\frac{1}{e}) ln (W_{0} (\frac{1}{e})) + W_{0} (\frac{1}{e})^{2} - 1

Axis interception points of

2 x ln (x) + x^{2} - 1 :

None

Asymptotes of

2 x ln (x) + x^{2} - 1 :

None

Extreme Points of

2 x ln (x) + x^{2} - 1 :

Minimum

(W_{0} (\frac{1}{e}), 2 W_{0} (\frac{1}{e}) ln (W_{0} (\frac{1}{e})) + W_{0} (\frac{1}{e})^{2} - 1)

Graph

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Frequently Asked Questions (FAQ)

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