What is the integral of 9cot^3(x)csc^3(x) ?

The integral of 9cot^3(x)csc^3(x) is -9(1/5 csc^5(x)-1/3 csc^3(x))+C

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integral of 9cot^3(x)csc^3(x)

\int 9 cot^{3} (x) csc^{3} (x) d x

- 9 (\frac{1}{5} csc^{5} (x) - \frac{1}{3} csc^{3} (x)) + C

Solution steps

\int 9 cot^{3} (x) csc^{3} (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 9 \cdot \int cot^{3} (x) csc^{3} (x) d x

Apply u-substitution

: \int - u^{2} (u^{2} - 1) d u

= 9 \cdot \int - u^{2} (u^{2} - 1) d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 9 (- \int u^{2} (u^{2} - 1) d u)

Expand

u^{2} (u^{2} - 1) : u^{4} - u^{2}

= 9 (- \int u^{4} - u^{2} d u)

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 9 (- (\int u^{4} d u - \int u^{2} d u))

\int u^{4} d u = \frac{u ^{5}}{5}

\int u^{2} d u = \frac{u ^{3}}{3}

= 9 (- (\frac{u ^{5}}{5} - \frac{u ^{3}}{3}))

Substitute back

u = csc (x)

= 9 (- (\frac{csc ^{5} ( x )}{5} - \frac{csc ^{3} ( x )}{3}))

Simplify

9 (- (\frac{csc ^{5} ( x )}{5} - \frac{csc ^{3} ( x )}{3})) : - 9 (\frac{1}{5} csc^{5} (x) - \frac{1}{3} csc^{3} (x))

= - 9 (\frac{1}{5} csc^{5} (x) - \frac{1}{3} csc^{3} (x))

Add a constant to the solution

= - 9 (\frac{1}{5} csc^{5} (x) - \frac{1}{3} csc^{3} (x)) + C

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What is the integral of 9cot^3(x)csc^3(x) ?
The integral of 9cot^3(x)csc^3(x) is -9(1/5 csc^5(x)-1/3 csc^3(x))+C