What is the first derivative of 5+2x^2 ?

The first derivative of 5+2x^2 is 4x

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derivative of 5+2x^2

\frac{d}{d x} (5 + 2 x^{2})

4 x

Solution steps

\frac{d}{d x} (5 + 2 x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (5) + \frac{d}{d x} (2 x^{2})

\frac{d}{d x} (5) = 0

\frac{d}{d x} (2 x^{2}) = 4 x

= 0 + 4 x

Simplify

= 4 x

x^{2} - 2 x + 2, g (3) = 2 x - 2, [0, 3]

b^{2}

\frac{1}{x ^{2} + 1}

x \to 0 - lim (arctan (\frac{1}{x}) + π)

\frac{d}{d x} (\frac{5}{4 x})