What is the integral of 30(x+2)(x+3)^4 ?

The integral of 30(x+2)(x+3)^4 is 30((x^6)/6+(14x^5)/5+(39x^4)/2+72x^3+(297x^2)/2+162x)+C

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integral of 30(x+2)(x+3)^4

\int 30 (x + 2) (x + 3)^{4} d x

30 (\frac{x ^{6}}{6} + \frac{14 x ^{5}}{5} + \frac{39 x ^{4}}{2} + 72 x^{3} + \frac{297 x ^{2}}{2} + 162 x) + C

Solution steps

\int 30 (x + 2) (x + 3)^{4} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 30 \cdot \int (x + 2) (x + 3)^{4} d x

Expand

(x + 2) (x + 3)^{4} : x^{5} + 14 x^{4} + 78 x^{3} + 216 x^{2} + 297 x + 162

= 30 \cdot \int x^{5} + 14 x^{4} + 78 x^{3} + 216 x^{2} + 297 x + 162 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 30 (\int x^{5} d x + \int 14 x^{4} d x + \int 78 x^{3} d x + \int 216 x^{2} d x + \int 297 x d x + \int 162 d x)

\int x^{5} d x = \frac{x ^{6}}{6}

\int 14 x^{4} d x = \frac{14 x ^{5}}{5}

\int 78 x^{3} d x = \frac{39 x ^{4}}{2}

\int 216 x^{2} d x = 72 x^{3}

\int 297 x d x = \frac{297 x ^{2}}{2}

\int 162 d x = 162 x

= 30 (\frac{x ^{6}}{6} + \frac{14 x ^{5}}{5} + \frac{39 x ^{4}}{2} + 72 x^{3} + \frac{297 x ^{2}}{2} + 162 x)

Add a constant to the solution

= 30 (\frac{x ^{6}}{6} + \frac{14 x ^{5}}{5} + \frac{39 x ^{4}}{2} + 72 x^{3} + \frac{297 x ^{2}}{2} + 162 x) + C

f (x) = x^{4} - 3 x^{3} - 9 x^{2} + 5 x

\int_{0}^{\frac{π}{2}} (sin (x)) d x

y^{^{''}} - 7 y^{^{'}} + 12 y = - 2 cos (3 t)

(1 + x^{5}) y^{^{'}} + 5 x^{4} y = 13 x^{4}

\int \frac{( x - 3 )}{x} d x

What is the integral of 30(x+2)(x+3)^4 ?
The integral of 30(x+2)(x+3)^4 is 30((x^6)/6+(14x^5)/5+(39x^4)/2+72x^3+(297x^2)/2+162x)+C