What is the integral from 0 to pi/2 of (sin(x)) ?

The integral from 0 to pi/2 of (sin(x)) is 1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to pi/2 of (sin(x))

\int_{0}^{\frac{π}{2}} (sin (x)) d x

1

Solution steps

\int_{0}^{\frac{π}{2}} sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= [- cos (x)]_{0}^{\frac{π}{2}}

Compute the boundaries:

1

= 1

y^{^{''}} - 7 y^{^{'}} + 12 y = - 2 cos (3 t)

(1 + x^{5}) y^{^{'}} + 5 x^{4} y = 13 x^{4}

\int \frac{( x - 3 )}{x} d x

\frac{\partial}{\partial y} (sin (x) \cdot cos (y))

\frac{3 x}{x - 6}

What is the integral from 0 to pi/2 of (sin(x)) ?
The integral from 0 to pi/2 of (sin(x)) is 1