What is the derivative of 1/(8sqrt(x)) ?

The derivative of 1/(8sqrt(x)) is -1/(16x^{3/2)}

What is the first derivative of 1/(8sqrt(x)) ?

The first derivative of 1/(8sqrt(x)) is -1/(16x^{3/2)}

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\frac{d}{d x} (\frac{1}{8 x})

- \frac{1}{16 x ^{\frac{3}{2}}}

Solution steps

\frac{d}{d x} (\frac{1}{8 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{8} \frac{d}{d x} (\frac{1}{x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{1}{8} \frac{d}{d x} (x^{- \frac{1}{2}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{8} (- \frac{1}{2} x^{- \frac{1}{2} - 1})

Simplify

\frac{1}{8} (- \frac{1}{2} x^{- \frac{1}{2} - 1}) : - \frac{1}{16 x ^{\frac{3}{2}}}

= - \frac{1}{16 x ^{\frac{3}{2}}}

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What is the derivative of 1/(8sqrt(x)) ?
The derivative of 1/(8sqrt(x)) is -1/(16x^{3/2)}
What is the first derivative of 1/(8sqrt(x)) ?
The first derivative of 1/(8sqrt(x)) is -1/(16x^{3/2)}