What is area y=x^3+x^2+x-1,y=x^3+5 ?

The answer to area y=x^3+x^2+x-1,y=x^3+5 is 125/6

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area y=x^3+x^2+x-1,y=x^3+5

area

y = x^{3} + x^{2} + x - 1, y = x^{3} + 5

\frac{125}{6}

Decimal

20.83333 \dots

Solution steps

Apply the area formula:

\int_{- 3}^{2} x^{3} + x^{2} + x - 1 - (x^{3} + 5) d x

Solve

\int_{- 3}^{2} x^{3} + x^{2} + x - 1 - (x^{3} + 5) d x : \frac{125}{6}

The area is:

= \frac{125}{6}

\frac{d y}{d t} = 2 y + y^{5}, y (0) = 1

\frac{- 1}{s + 1}

\int \frac{x - 3}{x ^{3} - 2 x ^{2} + 3 x} d x

x \to 3 lim (\frac{1}{2 ^{x} - 8})

x \to 0 lim (\frac{x}{tan ( 5 x )})

What is area y=x^3+x^2+x-1,y=x^3+5 ?
The answer to area y=x^3+x^2+x-1,y=x^3+5 is 125/6