What is the solution for y^'=((x^5))/y ?

The solution for y^'=((x^5))/y is y=sqrt((x^6)/3+c_{1)},y=-sqrt((x^6)/3+c_{1)}

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y^'=((x^5))/y

y^{^{'}} = \frac{( x ^{5} )}{y}

y = \frac{x ^{6}}{3} + c_{1}, y = - \frac{x ^{6}}{3} + c_{1}

Solution steps

y^{'} (x) = \frac{( x ^{5} )}{y}

Solve separable ODE:

y = \frac{x ^{6}}{3} + c_{1}, y = - \frac{x ^{6}}{3} + c_{1}

y = \frac{x ^{6}}{3} + c_{1}, y = - \frac{x ^{6}}{3} + c_{1}

\int_{0}^{3 π} 3 x^{2} sin (\frac{1}{6} x) d x

x \to 1 lim (5 x + 1)

x \to 0 lim ((x)^{- 1 + x})

y^{^{''}} - 4 y^{^{'}} + 9 y = 0

\int_{0}^{2} x^{2} x^{3} + 1 d x

What is the solution for y^'=((x^5))/y ?
The solution for y^'=((x^5))/y is y=sqrt((x^6)/3+c_{1)},y=-sqrt((x^6)/3+c_{1)}