What is the limit as x approaches 0 of (x)^{-1+x} ?

The limit as x approaches 0 of (x)^{-1+x} is Does not exist

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limit as x approaches 0 of (x)^{-1+x}

x \to 0 lim ((x)^{- 1 + x})

Does not exist

Solution steps

x \to 0 lim (x^{- 1 + x})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (x^{- 1 + x}) = \infty

x \to 0 - lim (x^{- 1 + x}) =

Does not exist

= Does not exist

y^{^{''}} - 4 y^{^{'}} + 9 y = 0

\int_{0}^{2} x^{2} x^{3} + 1 d x

f (x) = \frac{7}{4 - x}, at x = - 1

\frac{\partial}{\partial x} (y^{4} sin (2 x))

x \to - 4 lim (\frac{x ^{2} - 9}{4 - x})

What is the limit as x approaches 0 of (x)^{-1+x} ?
The limit as x approaches 0 of (x)^{-1+x} is Does not exist