What is (\partial)/(\partial y)(xcos(y)sin(z)) ?

The answer to (\partial)/(\partial y)(xcos(y)sin(z)) is -xsin(y)sin(z)

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(\partial)/(\partial y)(xcos(y)sin(z))

\frac{\partial}{\partial y} (x cos (y) sin (z))

- x sin (y) sin (z)

Solution steps

\frac{\partial}{\partial y} (x cos (y) sin (z))

Treat

x, z

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= x sin (z) \frac{\partial}{\partial y} (cos (y))

Apply the common derivative:

\frac{\partial}{\partial y} (cos (y)) = - sin (y)

= x sin (z) (- sin (y))

Simplify

= - x sin (y) sin (z)

2 y^{^{'}} + 10 y = 80, y (0) = 0

\frac{\partial}{\partial x} (8 - 2 x^{2} - y^{2})

g (0) = (4 - 2 x) e^{n} - 4

x \to - 1 lim (5 - x^{2})

\frac{π x}{4}

What is (\partial)/(\partial y)(xcos(y)sin(z)) ?
The answer to (\partial)/(\partial y)(xcos(y)sin(z)) is -xsin(y)sin(z)