What is the derivative of 9e^{-x} ?

The derivative of 9e^{-x} is -9e^{-x}

What is the first derivative of 9e^{-x} ?

The first derivative of 9e^{-x} is -9e^{-x}

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\frac{d}{d x} (9 e^{- x})

- 9 e^{- x}

Solution steps

\frac{d}{d x} (9 e^{- x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 9 \frac{d}{d x} (e^{- x})

Apply the chain rule:

e^{- x} \frac{d}{d x} (- x)

= e^{- x} \frac{d}{d x} (- x)

\frac{d}{d x} (- x) = - 1

= 9 e^{- x} (- 1)

Simplify

= - 9 e^{- x}

\frac{d}{d θ} (5 + 5 sin (θ))

(- 1)^{^{'}}

\frac{\partial}{\partial x} (\frac{x - y}{x + z})

y^{^{'}} = \frac{- 1}{x} y + 2

\frac{d}{d t} (5 sin (t))

What is the derivative of 9e^{-x} ?
The derivative of 9e^{-x} is -9e^{-x}
What is the first derivative of 9e^{-x} ?
The first derivative of 9e^{-x} is -9e^{-x}