What is the derivative of 2x^3+3x^2-36x ?

The derivative of 2x^3+3x^2-36x is 6x^2+6x-36

What is the first derivative of 2x^3+3x^2-36x ?

The first derivative of 2x^3+3x^2-36x is 6x^2+6x-36

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\frac{d}{d x} (2 x^{3} + 3 x^{2} - 36 x)

6 x^{2} + 6 x - 36

Solution steps

\frac{d}{d x} (2 x^{3} + 3 x^{2} - 36 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{3}) + \frac{d}{d x} (3 x^{2}) - \frac{d}{d x} (36 x)

\frac{d}{d x} (2 x^{3}) = 6 x^{2}

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (36 x) = 36

= 6 x^{2} + 6 x - 36

\frac{s}{s ^{2}}

\int \frac{ln ( x )}{x 1 + ln ( x )} d x

\frac{( x + 1 )}{( x - 1 )}

f (x) = x^{2} + 3, (- 1, 4)

\int_{2}^{t} \frac{1}{5 x ^{2}} d x

What is the derivative of 2x^3+3x^2-36x ?
The derivative of 2x^3+3x^2-36x is 6x^2+6x-36
What is the first derivative of 2x^3+3x^2-36x ?
The first derivative of 2x^3+3x^2-36x is 6x^2+6x-36