What is inverse oflaplace s/(s^2) ?

The answer to inverse oflaplace s/(s^2) is 1

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inverse oflaplace s/(s^2)

inverse laplace

\frac{s}{s ^{2}}

1

Solution steps

L^{- 1} {\frac{s}{s ^{2}}}

Apply inverse transform rule:

L^{- 1} {F (s)} = f (t)

then

L^{- 1} {s F (s)} = \frac{d}{d t} f (t) + f (0)

For

\frac{s}{s ^{2}} : F (s) = \frac{1}{s ^{2}}

= \frac{d}{d t} (L^{- 1} {\frac{1}{s ^{2}}}) + L^{- 1} {\frac{1}{s ^{2}}} (0)

L^{- 1} {\frac{1}{s ^{2}}} : t

\frac{d t}{d t} = 1

Evaluate

t

at point

0 = 0

= 1

\int \frac{ln ( x )}{x 1 + ln ( x )} d x

\frac{( x + 1 )}{( x - 1 )}

f (x) = x^{2} + 3, (- 1, 4)

\int_{2}^{t} \frac{1}{5 x ^{2}} d x

\frac{d}{d x} ((x + 2)^{2} - 3 x)

What is inverse oflaplace s/(s^2) ?
The answer to inverse oflaplace s/(s^2) is 1