What is the derivative of (x+2^2-3x) ?

The derivative of (x+2^2-3x) is 2x+1

What is the first derivative of (x+2^2-3x) ?

The first derivative of (x+2^2-3x) is 2x+1

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\frac{d}{d x} ((x + 2)^{2} - 3 x)

2 x + 1

Solution steps

\frac{d}{d x} ((x + 2)^{2} - 3 x)

Simplify

(x + 2)^{2} - 3 x : x^{2} + x + 4

= \frac{d}{d x} (x^{2} + x + 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d x}{d x} + \frac{d}{d x} (4)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d x}{d x} = 1

\frac{d}{d x} (4) = 0

= 2 x + 1 + 0

Simplify

= 2 x + 1

\int \frac{8 x ^{2} - 7 x + 16}{x ^{3} + 4 x} d x

\int_{1}^{3} \frac{1}{x ^{3}} d x

x 3 - x^{2}

x \to 2 lim (\frac{1}{∣ 2 - x ∣})

y = - x^{2} + 8 x - 12, y = x^{2} - 8 x + 18, x = 3 x = 6

What is the derivative of (x+2^2-3x) ?
The derivative of (x+2^2-3x) is 2x+1
What is the first derivative of (x+2^2-3x) ?
The first derivative of (x+2^2-3x) is 2x+1