What is the derivative of y=-1.97x^2+0.51x+8.1 ?

The derivative of y=-1.97x^2+0.51x+8.1 is -3.94x+0.51

What is the first derivative of y=-1.97x^2+0.51x+8.1 ?

The first derivative of y=-1.97x^2+0.51x+8.1 is -3.94x+0.51

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derivative of

y = - 1.97 x^{2} + 0.51 x + 8.1

- 3.94 x + 0.51

Solution steps

\frac{d}{d x} (- 1.97 x^{2} + 0.51 x + 8.1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (1.97 x^{2}) + \frac{d}{d x} (0.51 x) + \frac{d}{d x} (8.1)

\frac{d}{d x} (1.97 x^{2}) = 3.94 x

\frac{d}{d x} (0.51 x) = 0.51

\frac{d}{d x} (8.1) = 0

= - 3.94 x + 0.51 + 0

Simplify

= - 3.94 x + 0.51

\int sin (26 x) cos (17 x) d x

\int x sin (k x) d x

2 x e^{x^{2}}

\frac{\partial}{\partial x} (nani)

\frac{d y}{d x}, y = \frac{9}{x}

What is the derivative of y=-1.97x^2+0.51x+8.1 ?
The derivative of y=-1.97x^2+0.51x+8.1 is -3.94x+0.51
What is the first derivative of y=-1.97x^2+0.51x+8.1 ?
The first derivative of y=-1.97x^2+0.51x+8.1 is -3.94x+0.51