What is implicit (dy)/(dx),y= 9/x ?

The answer to implicit (dy)/(dx),y= 9/x is (dy)/(dx)=-9/(x^2)

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implicit (dy)/(dx),y= 9/x

implicit derivative

\frac{d y}{d x}, y = \frac{9}{x}

\frac{d y}{d x} = - \frac{9}{x ^{2}}

Solution steps

y = \frac{9}{x}

Treat

y

y (x)

Differentiate both sides:

\frac{d y}{d x} = - \frac{9}{x ^{2}}

Isolate

\frac{d y}{d x} : \frac{d y}{d x} = - \frac{9}{x ^{2}}

\frac{d y}{d x} = - \frac{9}{x ^{2}}

x \to - 1 lim (\frac{1}{x ^{2} + 2 x + 1})

4^{s i n (x)}

sin (2 x) d x + cos (7 y) d y = 0, y (π^{2}) = π^{7}

\frac{d}{d x} (\frac{x}{5})

\frac{\partial}{\partial x} (y - x)

What is implicit (dy)/(dx),y= 9/x ?
The answer to implicit (dy)/(dx),y= 9/x is (dy)/(dx)=-9/(x^2)