What is the sum from n=0 to infinity of (x-2x^2)^n ?

The sum from n=0 to infinity of (x-2x^2)^n is Interval of convergence is-1/2 <x<1

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sum from n=0 to infinity of (x-2x^2)^n

n = 0 \sum \infty (x - 2 x^{2})^{n}

Interval of convergence is - \frac{1}{2} < x < 1

Solution steps

n = 0 \sum \infty (x - 2 x^{2})^{n}

Use the Root Test to compute the convergence interval

Interval of convergence is - \frac{1}{2} < x < 1

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What is the sum from n=0 to infinity of (x-2x^2)^n ?
The sum from n=0 to infinity of (x-2x^2)^n is Interval of convergence is-1/2 <x<1