What is the solution for y^{''}+4sqrt(3)y^'+12y=0 ?

The solution for y^{''}+4sqrt(3)y^'+12y=0 is y=c_{1}e^{-2sqrt(3)t}+c_{2}te^{-2sqrt(3)t}

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y^{''}+4sqrt(3)y^'+12y=0

y^{^{''}} + 43 y^{^{'}} + 12 y = 0

y = c_{1} e^{- 23 t} + c_{2} t e^{- 23 t}

Solution steps

y^{''} (t) + 43 y^{'} (t) + 12 y = 0

Solve linear ODE:

y = c_{1} e^{- 23 t} + c_{2} t e^{- 23 t}

y = c_{1} e^{- 23 t} + c_{2} t e^{- 23 t}

\int \frac{1}{7} e^{7 x} d x

\frac{e ^{- 2 s}}{s ^{2} - 3 s - 4}

\frac{d}{d x} (ln (11))

x \to 0 lim (1 - \frac{1}{x})

(x - \frac{6}{x}), at m = 0

What is the solution for y^{''}+4sqrt(3)y^'+12y=0 ?
The solution for y^{''}+4sqrt(3)y^'+12y=0 is y=c_{1}e^{-2sqrt(3)t}+c_{2}te^{-2sqrt(3)t}