What is the tangent of y=4x^2,(2,16) ?

The tangent of y=4x^2,(2,16) is y=16x-16

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tangent of y=4x^2,(2,16)

tangent of

y = 4 x^{2}, (2, 16)

y = 16 x - 16

Solution steps

Find the slope of

y = 4 x^{2} : \frac{d y}{d x} = 8 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 16

Find the line with slope m=

16

and passing through

(2, 16) : y = 16 x - 16

y = 16 x - 16

\int_{1}^{10} \frac{1}{x - 6} d x

f (x) = 5 x^{2}, at x = - 3, - 45

f (x) = x^{3} - 4 x

\frac{d}{d x} (\frac{sin ( x ^{2} )}{3 x})

\int x e^{x} d x