What is the solution for xy^'+3y=(2e^{2x})/(x^2) ?

The solution for xy^'+3y=(2e^{2x})/(x^2) is y=(e^{2x})/(x^3)+(c_{1})/(x^3)

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xy^'+3y=(2e^{2x})/(x^2)

x y^{^{'}} + 3 y = \frac{2 e ^{2 x}}{x ^{2}}

y = \frac{e ^{2 x}}{x ^{3}} + \frac{c _{1}}{x ^{3}}

Solution steps

x y^{'} (x) + 3 y = \frac{2 e ^{2 x}}{x ^{2}}

Solve linear ODE:

y = \frac{e ^{2 x}}{x ^{3}} + \frac{c _{1}}{x ^{3}}

y = \frac{e ^{2 x}}{x ^{3}} + \frac{c _{1}}{x ^{3}}

\frac{d}{d x} (cos (x) + x^{\frac{5}{4}})

y^{^{''}} - 4 y^{^{'}} - 5 y = 5 x

\int \frac{1}{s ^{2} ( s - 1 ) ^{2}} d s

\int 6 x^{2} + 1 d x

x \to 0 + lim (- \frac{1}{x ^{2}})

What is the solution for xy^'+3y=(2e^{2x})/(x^2) ?
The solution for xy^'+3y=(2e^{2x})/(x^2) is y=(e^{2x})/(x^3)+(c_{1})/(x^3)