What is the solution for (dy)/(dx)=2^{4x-y} ?

The solution for (dy)/(dx)=2^{4x-y} is y=(ln(2^{4x-2}+c_{1}))/(ln(2))

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(dy)/(dx)=2^{4x-y}

\frac{d y}{d x} = 2^{4 x - y}

y = \frac{ln ( 2 ^{4 x - 2} + c _{1} )}{ln ( 2 )}

Solution steps

\frac{d y}{d x} = 2^{4 x - y}

Solve separable ODE:

y = \frac{ln ( 2 ^{4 x - 2} + c _{1} )}{ln ( 2 )}

y = \frac{ln ( 2 ^{4 x - 2} + c _{1} )}{ln ( 2 )}

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f (x) = x \cdot ln (2 x + 1)

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What is the solution for (dy)/(dx)=2^{4x-y} ?
The solution for (dy)/(dx)=2^{4x-y} is y=(ln(2^{4x-2}+c_{1}))/(ln(2))