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Popular >

f(x)=x*ln(2x+1)

Solution

f (x) = x \cdot ln (2 x + 1)

Solution

Domain : x > - \frac{1}{2}

Range : f (x) \geq 0

X Intercepts : (0, 0), Y Intercepts : (0, 0)

Asymptotes : Vertical x = - \frac{1}{2}

Extreme Points : Minimum (0, 0)

+1

Interval Notation

Domain : (- \frac{1}{2}, \infty)

Solution steps

Domain of

x \cdot ln (2 x + 1) : x > - \frac{1}{2}

Range of

x \cdot ln (2 x + 1) : f (x) \geq 0

Axis interception points of

x \cdot ln (2 x + 1) :

X Intercepts

: (0, 0),

Y Intercepts

: (0, 0)

Asymptotes of

x \cdot ln (2 x + 1) :

Vertical

: x = - \frac{1}{2}

Extreme Points of

x \cdot ln (2 x + 1) :

Minimum

(0, 0)

Graph

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\int e^{2 t} cos (t) d t

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\frac{d}{d x} (\frac{1}{4} x^{2})

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h \to 0 lim (sin (h))

\frac{d}{d y} (2 x y^{2})

Frequently Asked Questions (FAQ)

What is the f(x)=x*ln(2x+1) ?
The f(x)=x*ln(2x+1) is