What is the limit as h approaches 0 of sin(h) ?

The limit as h approaches 0 of sin(h) is 0

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limit as h approaches 0 of sin(h)

h \to 0 lim (sin (h))

0

Solution steps

h \to 0 lim (sin (h))

Plug in the value

h = 0

= sin (0)

Use the following trivial identity:

sin (0) = 0

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= 0

\frac{d}{d y} (2 x y^{2})

(e^{x} - 1) sin (- 2 x)

\int e^{7 x} - \frac{1}{x} d x

\frac{d y}{d x} = (5 y + y^{2})

\int \frac{1}{p ( 1 - 0.05 p )} d p

What is the limit as h approaches 0 of sin(h) ?
The limit as h approaches 0 of sin(h) is 0