What is the solution for (dy)/(dx)=(5y+y^2) ?

The solution for (dy)/(dx)=(5y+y^2) is y= 5/(e^{-5x-c_{1)}-1}

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(dy)/(dx)=(5y+y^2)

\frac{d y}{d x} = (5 y + y^{2})

y = \frac{5}{e ^{- 5 x - c_{1}} - 1}

Solution steps

\frac{d y}{d x} = (5 y + y^{2})

Solve Bernoulli ODE:

y = \frac{5}{e ^{- 5 x - c_{1}} - 1}

y = \frac{5}{e ^{- 5 x - c_{1}} - 1}

\int \frac{1}{p ( 1 - 0.05 p )} d p

\int 12 sec^{2} (6 x) tan (6 x) d x

\int \frac{1}{( x + 1 ) ( x + 5 )} d x

\int tan^{3} (9 x) sec (9 x) d x

y = cos (a^{9} + x^{9})

What is the solution for (dy)/(dx)=(5y+y^2) ?
The solution for (dy)/(dx)=(5y+y^2) is y= 5/(e^{-5x-c_{1)}-1}