What is the solution for -derivative of (dy/(dx))+400y=0 ?

The solution for -derivative of (dy/(dx))+400y=0 is y=c_{1}e^{20x}+c_{2}e^{-20x}

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-derivative of (dy/(dx))+400y=0

- \frac{d}{d x} (\frac{d y}{d x}) + 400 y = 0

y = c_{1} e^{20 x} + c_{2} e^{- 20 x}

Solution steps

- \frac{d ^{2} y}{d x ^{2}} + 400 y = 0

Solve linear ODE:

y = c_{1} e^{20 x} + c_{2} e^{- 20 x}

y = c_{1} e^{20 x} + c_{2} e^{- 20 x}

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What is the solution for -derivative of (dy/(dx))+400y=0 ?
The solution for -derivative of (dy/(dx))+400y=0 is y=c_{1}e^{20x}+c_{2}e^{-20x}