What is the integral of 1/2 x^{4/3} ?

The integral of 1/2 x^{4/3} is 3/14 x^{7/3}+C

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integral of 1/2 x^{4/3}

\int \frac{1}{2} x^{\frac{4}{3}} d x

\frac{3}{14} x^{\frac{7}{3}} + C

Solution steps

\int \frac{1}{2} x^{\frac{4}{3}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int x^{\frac{4}{3}} d x

Apply the Power Rule

: \frac{3}{7} x^{\frac{7}{3}}

= \frac{1}{2} \cdot \frac{3}{7} x^{\frac{7}{3}}

Simplify

\frac{1}{2} \cdot \frac{3}{7} x^{\frac{7}{3}} : \frac{3}{14} x^{\frac{7}{3}}

= \frac{3}{14} x^{\frac{7}{3}}

Add a constant to the solution

= \frac{3}{14} x^{\frac{7}{3}} + C

n = 0 \sum \infty n n

y = \frac{x ^{2}}{x + 9}, (1, \frac{1}{10})

\frac{\partial}{\partial x} ((x y^{2} + x^{3})^{4})

x \to 2 lim (x^{3} - 3 x + 7)

\frac{d}{d x} (\frac{x}{5 - x ^{2}})

What is the integral of 1/2 x^{4/3} ?
The integral of 1/2 x^{4/3} is 3/14 x^{7/3}+C