What is (\partial)/(\partial x)(ln(4)e^x) ?

The answer to (\partial)/(\partial x)(ln(4)e^x) is 2ln(2)e^x

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(\partial)/(\partial x)(ln(4)e^x)

\frac{\partial}{\partial x} (ln (4) e^{x})

2 ln (2) e^{x}

Solution steps

\frac{\partial}{\partial x} (ln (4) e^{x})

Simplify

ln (4) e^{x} : 2 ln (2) e^{x}

= \frac{\partial}{\partial x} (2 ln (2) e^{x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 ln (2) \frac{\partial}{\partial x} (e^{x})

Apply the common derivative:

\frac{\partial}{\partial x} (e^{x}) = e^{x}

= 2 ln (2) e^{x}

4 x^{2} \cdot y^{^{'}} = y^{^{'}} + 9 x \cdot e^{- y}

\frac{\partial}{\partial x} (x^{13})

x^{2} - 5 x + 5

\frac{\partial}{\partial x} (y cos (x^{2} + y^{2}))

\frac{d}{d x} (\frac{- 1}{1 - x})

What is (\partial)/(\partial x)(ln(4)e^x) ?
The answer to (\partial)/(\partial x)(ln(4)e^x) is 2ln(2)e^x