What is (\partial)/(\partial x)(cos(x-y)) ?

The answer to (\partial)/(\partial x)(cos(x-y)) is -sin(x-y)

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(\partial)/(\partial x)(cos(x-y))

\frac{\partial}{\partial x} (cos (x - y))

- sin (x - y)

Solution steps

\frac{\partial}{\partial x} (cos (x - y))

Treat

y

as a constant

Apply the chain rule:

- sin (x - y) \frac{\partial}{\partial x} (x - y)

= - sin (x - y) \frac{\partial}{\partial x} (x - y)

\frac{\partial}{\partial x} (x - y) = 1

= - sin (x - y) \cdot 1

Simplify

= - sin (x - y)

\frac{d}{d x} (21 x e^{- 2 x})

f (x) = 2 x + 4

\int 2 x (x^{2} + 9)^{7} d x

\int \frac{5}{9 x ^{2} - 16} d x

f (x) = 6 x^{3} + 7

What is (\partial)/(\partial x)(cos(x-y)) ?
The answer to (\partial)/(\partial x)(cos(x-y)) is -sin(x-y)