What is the tangent of f(x)=arcsin(3x),\at x= 1/6 ?

The tangent of f(x)=arcsin(3x),\at x= 1/6 is y=2sqrt(3)x+pi/6-1/(sqrt(3))

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tangent of f(x)=arcsin(3x),\at x= 1/6

tangent of

f (x) = arcsin (3 x), at x = \frac{1}{6}

y = 23 x + \frac{π}{6} - \frac{1}{3}

Solution steps

Find the tangent point:

(\frac{1}{6}, \frac{π}{6})

Find the slope of

f (x) = arcsin (3 x) : \frac{df ( x )}{d x} = \frac{3}{1 - 9 x ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 23

Find the line with slope m=

23

and passing through

(\frac{1}{6}, \frac{π}{6}) : y = 23 x + \frac{π}{6} - \frac{1}{3}

y = 23 x + \frac{π}{6} - \frac{1}{3}

\int 1 + (2 x - \frac{1}{8 x})^{2} d x

\int_{- 3}^{1} (1 + 2 x) d x

(e^{12 x})^{^{'}}

\int sinh^{2} (x) cosh (x) d x

x \to 0 lim (x cos (\frac{1}{x ^{2}}))

What is the tangent of f(x)=arcsin(3x),\at x= 1/6 ?
The tangent of f(x)=arcsin(3x),\at x= 1/6 is y=2sqrt(3)x+pi/6-1/(sqrt(3))