What is the derivative of y=-x^2+3 ?

The derivative of y=-x^2+3 is -2x

What is the first derivative of y=-x^2+3 ?

The first derivative of y=-x^2+3 is -2x

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derivative of

y = - x^{2} + 3

- 2 x

Solution steps

\frac{d}{d x} (- x^{2} + 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (x^{2}) + \frac{d}{d x} (3)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (3) = 0

= - 2 x + 0

Simplify

= - 2 x

f (t) = 5 t sin (π t)

y^{^{''''}} + 2 \cdot y^{^{''}} + y = 0

\frac{\partial}{\partial y} (2 x y + 2 x)

\frac{d}{d x} (sin^{2} (8 x))

\frac{d y}{d x} + x y = x y^{2}

What is the derivative of y=-x^2+3 ?
The derivative of y=-x^2+3 is -2x
What is the first derivative of y=-x^2+3 ?
The first derivative of y=-x^2+3 is -2x