What is the limit as x approaches 0 of (sin^2(3x))/x ?

The limit as x approaches 0 of (sin^2(3x))/x is 0

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limit as x approaches 0 of (sin^2(3x))/x

x \to 0 lim (\frac{sin ^{2} ( 3 x )}{x})

0

Solution steps

x \to 0 lim (\frac{sin ^{2} ( 3 x )}{x})

Apply L'Hopital's Rule

: x \to 0 lim (\frac{3 sin ( 6 x )}{1})

= x \to 0 lim (\frac{3 sin ( 6 x )}{1})

Plug in the value

x = 0

= \frac{3 sin ( 6 \cdot 0 )}{1}

Simplify

\frac{3 sin ( 6 \cdot 0 )}{1} : 0

= 0

\frac{\partial}{\partial x} (y^{2} - x^{3} - 2 x)

y = \frac{( x + 8 )}{( x - 5 )}

(x^{2} - 1) cos (3 x)

x \to - 7 + lim (- \frac{8 x}{x + 7})

\frac{d}{d x} (\frac{3 x ^{2}}{2})

What is the limit as x approaches 0 of (sin^2(3x))/x ?
The limit as x approaches 0 of (sin^2(3x))/x is 0