What is the integral from 0 to 2pi of integral from 0 to a of p ?

The integral from 0 to 2pi of integral from 0 to a of p is pia^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 2pi of integral from 0 to a of p

\int_{0}^{2 π} \int_{0}^{a} p d p d t

π a^{2}

Solution steps

\int_{0}^{2 π} \int_{0}^{a} p d p d t

\int_{0}^{a} p d p = \frac{a ^{2}}{2}

= \int_{0}^{2 π} (\frac{a ^{2}}{2}) d t

\int_{0}^{2 π} (\frac{a ^{2}}{2}) d t = π a^{2}

= π a^{2}

\int \frac{1}{( x ^{2} + 1 ) arctan ( x )} d x

\int x^{2} \cdot cos (2 x) d x

\frac{d}{d x} (- \frac{2}{cos ( 2 x )} + \frac{8}{3})

\frac{\partial}{\partial x} (9 x^{2} cos (y^{6}))

\frac{d}{d x} (4 3 x + 2 ln (x) - 3 e^{x})

What is the integral from 0 to 2pi of integral from 0 to a of p ?
The integral from 0 to 2pi of integral from 0 to a of p is pia^2