What is area-x^2+2x,y=x^3+x^2-6x ?

The answer to area-x^2+2x,y=x^3+x^2-6x is 148/3

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area-x^2+2x,y=x^3+x^2-6x

area

- x^{2} + 2 x, y = x^{3} + x^{2} - 6 x

\frac{148}{3}

Decimal

49.33333 \dots

Solution steps

Apply the area formula:

\int_{- 4}^{2} x^{3} + x^{2} - 6 x - (- x^{2} + 2 x) d x

Solve

\int_{- 4}^{2} x^{3} + x^{2} - 6 x - (- x^{2} + 2 x) d x : \frac{148}{3}

The area is:

= \frac{148}{3}

y = x^{3} - 2 x^{2}, y = 2 x^{2} - 3 x

\frac{2}{( ( s + 2 ) ( s ^{2} - 4 ) )}

\int \frac{2}{- x ^{2} + 4 x} d x

\frac{d}{d θ} (4 + 4 sin (θ))

\frac{d}{d x} (x - 3 x^{\frac{1}{3}})

What is area-x^2+2x,y=x^3+x^2-6x ?
The answer to area-x^2+2x,y=x^3+x^2-6x is 148/3