What is the derivative of-216cos(3x) ?

The derivative of-216cos(3x) is 648sin(3x)

What is the first derivative of-216cos(3x) ?

The first derivative of-216cos(3x) is 648sin(3x)

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\frac{d}{d x} (- 216 cos (3 x))

648 sin (3 x)

Solution steps

\frac{d}{d x} (- 216 cos (3 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 216 \frac{d}{d x} (cos (3 x))

Apply the chain rule:

- sin (3 x) \frac{d}{d x} (3 x)

= - sin (3 x) \frac{d}{d x} (3 x)

\frac{d}{d x} (3 x) = 3

= - 216 (- sin (3 x) \cdot 3)

Simplify

= 648 sin (3 x)

\int_{0}^{1} (1 - e^{- t})^{2} d t

\int - 2 x sin (x^{2}) d x

y = 8 e^{x} + x, (0, 8)

f (x) = 6 sin (2 x)

y - 2 y^{^{'}} - 24 y = 0

What is the derivative of-216cos(3x) ?
The derivative of-216cos(3x) is 648sin(3x)
What is the first derivative of-216cos(3x) ?
The first derivative of-216cos(3x) is 648sin(3x)