What is the solution for (dx)/(dt)=0.03x+3600t ?

The solution for (dx)/(dt)=0.03x+3600t is x=-(399999999.99999…(0.03t+1))/(100)+c_{1}e^{0.03t}

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(dx)/(dt)=0.03x+3600t

\frac{d x}{d t} = 0.03 x + 3600 t

x = - \frac{399999999.99999 \dots ( 0.03 t + 1 )}{100} + c_{1} e^{0.03 t}

Solution steps

\frac{d x}{d t} = 0.03 x + 3600 t

Solve linear ODE:

x = - \frac{399999999.99999 \dots ( 0.03 t + 1 )}{100} + c_{1} e^{0.03 t}

x = - \frac{399999999.99999 \dots ( 0.03 t + 1 )}{100} + c_{1} e^{0.03 t}

\frac{2}{3 x + 5}

\frac{d}{d x} (\frac{5 x}{x + 4})

\int_{- 4}^{4} (3 - ∣ x ∣) d x

y = (x^{2} + 4)^{\frac{2}{3}}, at x = 2

y = 5 ln (4 x^{2} + 1)

What is the solution for (dx)/(dt)=0.03x+3600t ?
The solution for (dx)/(dt)=0.03x+3600t is x=-(399999999.99999…(0.03t+1))/(100)+c_{1}e^{0.03t}