What is the derivative of 8x^{-3} ?

The derivative of 8x^{-3} is -(24)/(x^4)

What is the first derivative of 8x^{-3} ?

The first derivative of 8x^{-3} is -(24)/(x^4)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (8 x^{- 3})

- \frac{24}{x ^{4}}

Solution steps

\frac{d}{d x} (8 x^{- 3})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 8 \frac{d}{d x} (x^{- 3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 8 (- 3 x^{- 3 - 1})

Simplify

8 (- 3 x^{- 3 - 1}) : - \frac{24}{x ^{4}}

= - \frac{24}{x ^{4}}

\frac{x}{11} - \frac{11}{x}

\int_{0}^{2 \cdot π} sin (t) d t

\frac{d}{d x} (3 x + x^{2})

\int 4 x cos (9 x) d x

\frac{d}{d x} (\frac{1}{8} ln (\frac{3 x - 4}{3 x + 4}))

What is the derivative of 8x^{-3} ?
The derivative of 8x^{-3} is -(24)/(x^4)
What is the first derivative of 8x^{-3} ?
The first derivative of 8x^{-3} is -(24)/(x^4)