What is (\partial)/(\partial x)((3xy-2)^2) ?

The answer to (\partial)/(\partial x)((3xy-2)^2) is 6y(3xy-2)

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(\partial)/(\partial x)((3xy-2)^2)

\frac{\partial}{\partial x} ((3 x y - 2)^{2})

6 y (3 x y - 2)

Solution steps

\frac{\partial}{\partial x} ((3 x y - 2)^{2})

Treat

y

as a constant

Apply the chain rule:

2 (3 x y - 2) \frac{\partial}{\partial x} (3 x y - 2)

= 2 (3 x y - 2) \frac{\partial}{\partial x} (3 x y - 2)

\frac{\partial}{\partial x} (3 x y - 2) = 3 y

= 2 (3 x y - 2) \cdot 3 y

Simplify

= 6 y (3 x y - 2)

\int_{4}^{9} x d x

f (x) = sin (x) + x cos (x)

f (x) = x + 3

t y^{^{'}} + 4 y = t^{2} - t + 1

f (x) = \frac{1}{x ^{5}}

What is (\partial)/(\partial x)((3xy-2)^2) ?
The answer to (\partial)/(\partial x)((3xy-2)^2) is 6y(3xy-2)