What is the integral from 0 to 2 of k(2-x) ?

The integral from 0 to 2 of k(2-x) is (2-x)*2

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integral from 0 to 2 of k(2-x)

\int_{0}^{2} k (2 - x)

(2 - x) \cdot 2

Solution steps

\int_{0}^{2} k (2 - x) d k

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= (2 - x) \cdot \int_{0}^{2} k d k

\int_{0}^{2} k d k = 2

= (2 - x) \cdot 2

y^{^{'}} + tan (x) y = cos (x)

\int x^{2} + 7 e^{x} + C d x

y^{^{''}} + 2 y^{^{'}} = 1

y^{^{''}} - 10 y^{^{'}} + 25 y = \frac{( - 3 e ^{5 x} )}{( x ^{2} + 1 )}

\frac{d}{d x} (- 2 + \frac{7}{4 x})

What is the integral from 0 to 2 of k(2-x) ?
The integral from 0 to 2 of k(2-x) is (2-x)*2