What is the derivative of y=sin^5(2x+1) ?

The derivative of y=sin^5(2x+1) is 10sin^4(2x+1)cos(2x+1)

What is the first derivative of y=sin^5(2x+1) ?

The first derivative of y=sin^5(2x+1) is 10sin^4(2x+1)cos(2x+1)

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derivative of

y = sin^{5} (2 x + 1)

10 sin^{4} (2 x + 1) cos (2 x + 1)

Solution steps

\frac{d}{d x} (sin^{5} (2 x + 1))

Apply the chain rule:

5 (sin (2 x + 1))^{4} \frac{d}{d x} (sin (2 x + 1))

= 5 (sin (2 x + 1))^{4} \frac{d}{d x} (sin (2 x + 1))

\frac{d}{d x} (sin (2 x + 1)) = cos (2 x + 1) \cdot 2

= 5 (sin (2 x + 1))^{4} cos (2 x + 1) \cdot 2

Simplify

= 10 sin^{4} (2 x + 1) cos (2 x + 1)

f (x) = - csc (x) - sin (x)

\frac{d}{d x} (3 x^{2} + x + 1)

\int_{1}^{e^{3}} \frac{ln ^{2} ( x ^{2} )}{x} d x

e^{t - 2}

f (t) = 3 e^{t}

What is the derivative of y=sin^5(2x+1) ?
The derivative of y=sin^5(2x+1) is 10sin^4(2x+1)cos(2x+1)
What is the first derivative of y=sin^5(2x+1) ?
The first derivative of y=sin^5(2x+1) is 10sin^4(2x+1)cos(2x+1)