What is the derivative of f(x)=ln(4sin^2(x)) ?

The derivative of f(x)=ln(4sin^2(x)) is 2cot(x)

What is the first derivative of f(x)=ln(4sin^2(x)) ?

The first derivative of f(x)=ln(4sin^2(x)) is 2cot(x)

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derivative of

f (x) = ln (4 sin^{2} (x))

2 cot (x)

Solution steps

\frac{d}{d x} (ln (4 sin^{2} (x)))

Apply the chain rule:

\frac{1}{4 sin ^{2} ( x )} \frac{d}{d x} (4 sin^{2} (x))

= \frac{1}{4 sin ^{2} ( x )} \frac{d}{d x} (4 sin^{2} (x))

\frac{d}{d x} (4 sin^{2} (x)) = 4 sin (2 x)

= \frac{1}{4 sin ^{2} ( x )} \cdot 4 sin (2 x)

Simplify

\frac{1}{4 sin ^{2} ( x )} \cdot 4 sin (2 x) : 2 cot (x)

= 2 cot (x)

\int e^{- x} \cdot \frac{1}{x} d x

- 2 sin (θ)

\frac{d}{d x} (x^{8 s i n (x)})

\frac{d y}{d x} = y^{4}

\frac{\partial}{\partial y} (sin (π (4 x - 6 y)))

What is the derivative of f(x)=ln(4sin^2(x)) ?
The derivative of f(x)=ln(4sin^2(x)) is 2cot(x)
What is the first derivative of f(x)=ln(4sin^2(x)) ?
The first derivative of f(x)=ln(4sin^2(x)) is 2cot(x)