What is the integral of 3cos(n)x ?

The integral of 3cos(n)x is 3/2 x^2cos(n)+C

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integral of 3cos(n)x

\int 3 cos (n) x d x

\frac{3}{2} x^{2} cos (n) + C

Solution steps

\int 3 cos (n) x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 cos (n) \cdot \int x d x

Apply the Power Rule

: \frac{x ^{2}}{2}

= 3 cos (n) \frac{x ^{2}}{2}

Simplify

3 cos (n) \frac{x ^{2}}{2} : \frac{3}{2} x^{2} cos (n)

= \frac{3}{2} x^{2} cos (n)

Add a constant to the solution

= \frac{3}{2} x^{2} cos (n) + C

n = 1 \sum \infty \frac{2}{1 + e ^{n}}

\frac{d}{d x} (\frac{( x - 3 )}{x + 3})

\int_{0}^{4} (e^{- 0.25 x} + 5) d x

\frac{1}{( s ^{2} + 1 ) ( s ^{2} )}

x \to 0 + lim (arccot (x))