What is the limit as x approaches 0+of arccot(x) ?

The limit as x approaches 0+of arccot(x) is pi/2

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limit as x approaches 0+of arccot(x)

x \to 0 + lim (arccot (x))

\frac{π}{2}

Decimal

1.57079 \dots

Solution steps

x \to 0 + lim (arccot (x))

Plug in the value

x = 0

= arccot (0)

Use the following trivial identity:

arccot (0) = \frac{π}{2}

x - 3 - 1 - \frac{3}{3} 0 \frac{3}{3} 13 arccot (x) \frac{5 π}{6} \frac{3 π}{4} \frac{2 π}{3} \frac{π}{2} \frac{π}{3} \frac{π}{4} \frac{π}{6} arccot (x) 15 0^{\circ} 13 5^{\circ} 12 0^{\circ} 9 0^{\circ} 6 0^{\circ} 4 5^{\circ} 3 0^{\circ}

= \frac{π}{2}

\int (2 x^{2} + 3 x - 3) (5 x + 3) d x

f (x) = \frac{x ^{4}}{8} - 8 x

x \to \infty lim (5 + \frac{1}{x})

\frac{d}{d x} ((x^{2} + 1)^{x})

x \to 3 lim (4 + 4 (- 4))

What is the limit as x approaches 0+of arccot(x) ?
The limit as x approaches 0+of arccot(x) is pi/2